I have an XML with timestamps like this:
<node stamp="1236888746689" />
And I would like to display them in the result HTML as date with time. Is there a way to do it with XSLT (any Version)?
EDIT: I am using XSLT2.0 with Saxon9. The base date is 1970-01-01 0:00.
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XSLT is Turing complete, so there must be a way. :) Knowing at least a bit of XSLT, it will probably involve recursion.
You don't specify the exact interpretation of your "ticks", I'm guessing milliseconds since some epoch, but which? 1970?
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You take the date 1970-01-01T00:00:00 and add as many milliseconds as the value of stamp tell you:
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns="http://www.w3.org/TR/xhtml1/strict"> <xsl:template match="node"> <xsl:value-of select='xs:dateTime("1970-01-01T00:00:00") + @stamp * xs:dayTimeDuration("PT0.001S")'/> </xsl:template> </xsl:stylesheet>
Broam : How would one modify the answer to use the inner text in a node, instead of an attribute on it? -
If you wanted to use an XSL 1.0 processor that does not support the EXSLT date and time functions this is non-trivial, but it has been done.
You can have a look at Katy Coe's XSLT 1.0 implementation of the "iso-from-unix" function. It's part of a rather huge "free for non-commercial use" set of date and time functions she created.
However, your XSL processor must support the
"http://exslt.org/functions"
namespace for this implementation to work. Other than that there is no dependency on EXSLT.P.S.: I'm aware that a Unix timestamp and ticks are not exactly the same thing. They are close enough, though.
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If you are using an XSLT 1.0 processor which supports the EXSLT date functions (I've just tested this with libxslt in PHP), you can use
date:add()
anddate:duration()
:<xsl:value-of select="date:add('1970-01-01T00:00:00Z', date:duration(@stamp div 1000))"/>
The
date:duration()
function takes a number of seconds (so you have to divide your milliseconds by 1000) and turns it into a "duration" (in this case, "P14315DT20H12M26.6889998912811S
"), which is then added to the start of your epoch (looks like the standard epoch, for this stamp) withdate:add()
to get a stamp of "2009-03-12T20:12:26.6889998912811Z
". You can then format this using the EXSLT date functions or justsubstring()
, depending on what you need.
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